Free Capitalist Network - Community Archive
Mises Community Archive
An online community for fans of Austrian economics and libertarianism, featuring forums, user blogs, and more.

Ron Paul No. 2 in Delegate Count?

rated by 0 users
This post has 4 Replies | 0 Followers

Top 50 Contributor
Posts 2,028
Points 51,580
limitgov Posted: Wed, Feb 29 2012 12:05 PM

Ron Paul keeps saying he's number two in delegate count.  Yet on CNN's website, he's not.

http://www.cnn.com/election/2012/primaries/scorecard/statebystate/r

 

What gives?  Is CNN wrong? 

  • | Post Points: 20
Top 10 Contributor
Posts 6,953
Points 118,135
John James replied on Wed, Feb 29 2012 12:14 PM

Technically yes.  They are simply making a guess.  All those delegates haven't been assigned yet.  So in terms of actual pledged delegates, Paul is 2nd.

 

  • | Post Points: 20
Top 75 Contributor
Posts 1,037
Points 17,975
John Ess replied on Thu, Mar 1 2012 12:28 PM

Looks like he is in third, in pledged delegates, Mr. James.  gingrich has more total, but paul has more pledged.

  • | Post Points: 20
Top 10 Contributor
Posts 6,953
Points 118,135

Now that may be the case...He was saying "second" at least 3 states ago.

 

  • | Post Points: 20
Top 75 Contributor
Posts 1,037
Points 17,975

Gingrich does need to hang it up.

Paul can afford to weather the storm even after some losses, since he is radical and just trying to spread the message of peace and libertarianism. 

But Gingrich wants the broad support of being a generic neocon.  And if you can't win against Santorum or Romney, who basically fit that bill perfectly, there is no need for a third clone.

More than anything I think Gingrich is losing because he is ugly, pudgy, and he has helmet hair.  He's so nineties.  While Santorum and Romney actually look like presidents, even if they are terrible people.  I can't imagine anyone sees any difference between them, other than Santorum wrapping his brand of fascism in the Bible.

  • | Post Points: 5
Page 1 of 1 (5 items) | RSS